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8n^2-56n=0
a = 8; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·8·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*8}=\frac{0}{16} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*8}=\frac{112}{16} =7 $
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